1st PUC physics Series-3 wefruPUC Science 1st Year Physics Series-3 quiz 0 Created on December 02, 2020 By wefru1st PUC Physics Series 3TEST YOUR KNOWLEDGE OF SCIENCE 1 / 10Q.21 The time period of a simple pendulum is T remaining at rest inside a lift. Find the time period of the pendulum when the lift starts to move up with an acceleration of g/3 T√3/2 T√3 √3/20 20 2 / 10Q.22 The length of the second’s pendulum on the surface of the earth is 1m. The length of the same pendulum on the surface of the moon, where the acceleration due to gravity is (⅙)^{th} of the g on the surface of the earth is ⅙ m 3 m 4 m 8 m 3 / 10Q.23 The displacement of a particle performing simple harmonic motion is given by,x= 8 sin ωt + 6 cos ωt, where distance is in cm and time is in second. The amplitude of motion is 10 m 20 m 30 m 40 m 4 / 10Q.24 A particle executes S.H.M of amplitude A. At what distance from the mean position is its kinetic energy equal to its potential energy? 0.71 A 20.1 A 30.5 A 80.3 A 5 / 10Q.25 A simple pendulum on length l and mass m is suspended vertically. The string makes an angle θ with the vertical. The restoring force acting on the pendulum is – mg sinθ – mg cosθ mg tanθ mg sinθ 6 / 10Q.26 The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (if it is a second’s pendulum on earth) 2 x √2 second √2 second 22 second 252 second 7 / 10Q.27 A particle of mass m is hanging vertically by an ideal spring of force constant k. If the mass is made to oscillate vertically, its total energy is Same at all positions Maximum at mean position Minimum at mean position Maximum at extreme position 8 / 10Q.28 A a place where g = 980 cm/sec^{2 }the length of seconds pendulum is about 100 cm 20 cm 30 cm 56 cm 9 / 10Q.29 The maximum velocity for a particle in S.H.M is 0.16 m/s and maximum acceleration is 0.64 m/s^{2 .}The amplitude is 4 x 10-2 m 8 x 10-2 m 12 x 10-2 m 456 x 10-2 m 10 / 10Q.30 For a magnet of a time period T magnetic moment is M. If the magnetic moment becomes one-fourth of the initial value, then the time period of oscillation becomes Double of the initial value Half of the initial value One-fourth of the initial value Four times the initial value Your score isThe average score is 0% LinkedIn Facebook Twitter VKontakte 0% Restart quiz Related